Question 116567
This is a typical "set-up" math problem meant to teach you something. 
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You might guess that the quadratic expression {{{x^2 + 10x + 24}}} can be factored. And 
since the divisor is {{{x + 4}}} you might also guess that in this "set-up" it will be one 
of the factors of the quadratic.
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As a matter of fact, that's just exactly what happens. Start with:
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{{{(x^2 + 10x + 24)/(x + 4)}}}
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Factor the quadratic numerator to get:
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{{{((x + 6)(x+4))/(x + 4)}}}
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Cancel the like terms in the numerator and denominator:
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{{{((x + 6)cross(x+4))/cross(x + 4)}}}
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And you are left with the answer:
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{{{x + 6}}}
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Don't always expect things to work out this nicely. Lots of times in "real life" the quadratic 
can not be factored ... or the denominator is not one of the factors of the quadratic ... 
or some other "glitch". This problem just happens to be an example of a process that you might 
try as a method of solving the problem.
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Hope this helps you to learn a little more about this method of problem solving.
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