Question 1208876
Written more clearly,  As many nickels as pennies, three more dimes than nickels, and five fewer quarters than pennies.  He has  $3.97.



<pre>
COIN        QUANTITY       AMOUNT
penny          x            0.01x
nickel         x            0.05x
dime           x+3          0.1(x+3)
quarter        x-5          0.25(x-5)

TOTAL                       3.97
</pre>

{{{0.06x+0.1(x+3)+0.25(x-5)=3.97}}}


{{{0.06x+0.3+9.1x-0.25*5+0.25x=3.97}}}

{{{(0.06+0.1+0.25)x+0.3-0.25*5=3.97}}}

{{{0.41x=3.97-0.3+1.25}}}

{{{0.41x=4.92}}}

{{{x=4.92/0.41}}}

{{{highlight(x=12)}}}, and from this you can find the others.