Question 1208864
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Here are a couple of non-algebraic methods for solving the problem.<br>
(1) by logical reasoning and simple arithmetic....<br>
If all 50 vehicles had been cars, the amount they would have collected is 50($4) = $200
but the actual amount was $10 more than that
they collect $2 more for each truck than for each car
the number of trucks they had to wash to make the additional $10 is $10/$2 = 5.<br>
ANSWER: 5 trucks (and 50-5 = 45 cars)<br>
(2) as an unusual type of "mixture" problem....<br>
You are "mixing" cars at $4 each and trucks at $6 each and getting an average of $210/50 = $4.20<br>
Use a number line if it helps to see that $4.20 is 1/10 of the way from $4 to $6.<br>
That means 1/10 of the total 50 vehicles were trucks.<br>
ANSWER (again, of course): 5 trucks and 45 cars<br>