Question 116567


The Distributive Property is handy to help you get rid of parentheses. 
{{{a(b + c) = ab + ac }}}


	{{{(x ^2+10x+24)/ (x+4)}}}………. replace {{{10x}}} with {{{4x + 6x}}} 

{{{(x ^2 + 4x + 6x + 24)/ (x+4)}}}………. group the first two terms together and the last two terms together like this:
	
{{{((x ^2 + 4x) + (6x + 24))/ (x+4)}}}………. factor a {{{x}}} out of the first group and factor a {{{6}}} out of the second group

{{{(x(x + 4) + 6(x + 4))/ (x+4)}}}………. we have a common term {{{x+4}}} and we can combine the two terms

{{{(x + 6)(x + 4)/ (x+4)}}}……….cancel {{{x+4}}}


{{{x + 6}}}……….your answer