Question 1208814
.
Solve for x.

(x + 1)^2 + (x - 1)^2 = 2x
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
(x + 1)^2 + (x - 1)^2 = 2x

(x^2 + 2x + 1) + (x^1 - 2x + 1) = 2x

2x^2 + 2 = 2x

2x^2 - 2x + 2 = 0

x^2 - x + 1 = 0.


Use the quadratic formula and get two solutions in complex numbers

{{{x[1]}}} = {{{(1 + i*sqrt(3))/2}}}  and  {{{x[2]}}} = {{{(1 - i*sqrt(3))/2}}}.    <U>ANSWER</U>


There is no real solutions.
</pre>

Solved.