Question 1208815
.
Solve for x: [(1/(2x)]^2 + [(2/(3x)]^2 = 47x.
~~~~~~~~~~~~~~~~~~~~~~


<pre>
This equation is equivalent to

    {{{1/(4x^2)}}} + {{{4/(9x^2)}}} = 47x.


Write with the common denominator on the left side

    {{{9/(36x^2)}}} + {{{16/(36x^2)}}} = 47x

    {{{(9+16)/(36x^2)}}} = 47x,

    {{{25/(36x^2)}}} = 47x,

    x^3 = {{{25/(36*47)}}},

    x = {{{root(3, 25/1692)}}} = 0.245384174  (rounded).    <U>ANSWER</U>
</pre>

Solved.