Question 1208819
{{{(x-2)^2+(y-7)^2=25}}}, and {{{y=5x-28}}}


and then {{{(x-2)^2+((5x-28)-7)^2=25}}}


{{{(x-2)^2+(5x-35)^2=25}}}


{{{x^2-4x+4+25x^2-2*5*35x+35^2=25}}}


{{{26x^2-4x-350x+4+35^2=25}}}


{{{26x^2-354x+1229=25}}}


{{{26x^2-354x+1204=0}}}


{{{13x^2-177x+602=0}}}

Maybe that is factorable, and maybe not.  You can use general quadratic formula solution to find x.



{{{x=(177+- 5)/26}}}
and see where that takes you.