Question 1208766
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Let's consider the range of the sine function. {{{sin(x)}}} must always be between -1 and 1. 


This means that {{{sin^2(x)}}} must always be between 0 and 1. 


Combining these two means that {{{sin^2(x)+sin(x)}}} must always be between -1 and 2. 


Finally, adding 4 means {{{sin^2(x)+sin(x)+4}}} must be between 3 and 6. 


Therefore, there are no solutions. (assuming x is real)