Question 1208743
<pre>
Since you're probably an algebra student, maybe you'd like to see a solution
with an unknown or two, and not just basic arithmetic.

Suppose the siblings consist of b boys and g girls.
Since nobody can be their own brother or sister,
each boy has b-1 brothers and g sisters, and
each girl has b brothers and g-1 sisters. 

<font color="blue"><b>If I have 2 more sisters then brothers...</b></font>

If "I" is a boy, then he has b-1 brothers and g sisters, and g=(b-1)+2, or g=b+1

<font color="blue"><b>...and each of my sisters also has 2 more sisters than brothers...</b></font>

But then each of his sisters would have g-1 sisters and b brothers, and we would
have g-1=b+2 or g=b+3, not g=b+1. So "I" is not a boy. So "I" is a girl.

Then she and each of her sisters have b brothers and g-1 sisters, and
g-1=b+2 or g=b+3

<font color="blue"><b>how many more sisters than brothers does my oldest brother have?</b></font> 

Each of her brothers, including the oldest, has b-1 brothers and g=b+3 sisters.

So g-(b-1) = (b+3)-(b-1) = b+3-b+1 = 4

Answer: 4

Edwin</pre>