Question 116528
I'm guessing a little, but I think you meant {{{x^2+4x-1=0}}}.


*[invoke quadratic "x",1,4,-1]


Instead of calculating the answer to a bunch of meaningless decimal places like this solver does, I would just leave the answer in terms of a radical.


{{{x=(-4+-sqrt(20))/2}}}
{{{x=(-4+2*sqrt(5))/2}}} or {{{x=(-4-2*sqrt(5))/2}}}
{{{x=-2+sqrt(5)}}} or {{{x=-2-sqrt(5)}}}