Question 1208689
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Fill in the blanks with positive integers:
(3 + sqrt(6))^3 = ___ + ___ * sqrt(6)
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<pre>
Use the identity

    {{{(a+b)^3}}} = {{{a^3}}} + {{{3a^2*b}}} + {{{3a*b^2}}} + {{{b^3}}}.


It gives

       {{{(3 + sqrt(6))^3}}} = {{{3^3 + 3*3^2*sqrt(6) + 3*3*(sqrt(6))^2 + (sqrt(6))^3}}} = {{{27 + 27*sqrt(6) + 9*6 + 6*sqrt(6)}}} = {{{81 + 33*sqrt(6)}}}.


So, the blanks are 81 and 33.     <U>ANSWER</U>
</pre>

Solved.