Question 116524
{{{8x^2-4x=0}}}


There is at least one x in each of the terms, so factor that out:
{{{x(8x-4)=0}}}


This equation is true if and only if {{{x=0}}} or {{{8x-4=0}}}, so {{{x=0}}} or {{{x=4/8=1/2}}}