Question 1208662
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Solve for a.

(a/x)^3 + (b/x) = c
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You start from

    {{{(a/x)^3}}} + {{{b/x}}} = c.


    As your starting equation is written in this form, 
    it is assumed implicitly that x =/=0.


Isolate the term with "a" in the left side

    {{{(a/x)^3}}} = c - {{{b/x}}}.


Since left side is the fraction, write right side as a fraction, too

    {{{(a/x)^3}}} = {{{(cx - b)/x}}}.


It is the same as 

    {{{a^3/x^3}}} = {{{(cx-b)/x}}}.


Multiply both sides by  {{{x^3}}}

    {{{a^3}}} = {{{(x^3*(cx-b))/x}}} = {{{x^2*(cx-b)}}}


Now take cube roots of both sides

    a =  {{{root(3, x^2*(cx-b))}}}.


It is the desired expression for "a".
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Solved.