Question 1208644
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Consider triangle ABC.


Its side AB is 35 kilometers long..

Its side AC is 70 kilometers long.


The angle A is 50 degrees + 90 degrees + 30 degrees = 170 degrees.


To find the length of the side BC, use the cosine law

    BC = {{{sqrt(AB^2 + BC^2 - 2*cos(A)*AB*AC)}}} = {{{sqrt(35^2 + 70^2 - 2*35*70*(-0.98481))}}} = 104.645 km  (rounded).


<U>ANSWER</U>.  The distance from A to C is about 104.6 kilometers.
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Solved.