Question 1208637
You can take the original length of each candle to both be a unit of 1, for 1 candle length.  Then for some expected time, since both are started at the same time,  candle  #1 will be {{{1-(1/4)x}}} and candle #2 will be {{{2(1-(1/3)x)}}}. 


You would have then  {{{1-x/4=2(1-x/3)}}}.
Simplify this and solve for the time, x.