Question 1208368
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log16/log32
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<pre>
{{{log((16))/log((32))}}} = {{{log((2^4))/log((2^5))}}} = {{{(4*log((2)))/(5*log((2)))}}} = reduce log(2) = {{{4/5}}} = 0.8.


Interesting that it is true for any base of logarithms.
</pre>

Solved.