Question 1208369
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log16/log32, log36-log9
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<pre>
{{{log((16))/log((32))}}} = {{{log((2^4))/log((2^5))}}} = {{{(4*log((2)))/(5*log((2)))}}} = reduce log(2) = {{{4/5}}} = 0.8.


log(36)-log(9) = {{{log((36/9))}}} = log(4) = {{{log((2^2))}}} = {{{2*log(2)}}}.
</pre>

Solved: simplified.