Question 1208359
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{{{sqrt(4x^3*9y^5)}}}


= {{{sqrt(36x^2*x*y^4*y)}}}


= {{{sqrt((36x^2y^4)*xy)}}}


= {{{sqrt((6xy^2)^2*xy)}}}


= {{{sqrt((6xy^2)^2)*sqrt(xy)}}}


= {{{6xy^2*sqrt(xy)}}} where {{{x >= 0}}} and {{{y >= 0}}}
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