Question 1208272
<pre>

When a digit is repeated three times, it is repeated two times. 

They are either the arrangements of XXYYZ or of XXYYY, where different
letters represent different digits.

Case 1.  The arrangements of XXYYZ.
Choose the X 5 ways.
Choose the Y 4 ways.
Choose the Z 3 ways.
That's (5)(4)(3)=60 ways.

We divide by two because, for instance, XXYYZ could be chosen respectively, as
33556 or 55336, which are the same.

So that's 30 ways. to select the three digits.

They may be ordered in {{{5!/(2!2!)}}}{{{""=""}}}{{{30}}} distinguishable ways.

That's (30)(30) = 900 ways

Case 2: The arrangements of XXYYY

Choose the digit for X in 5 ways.
Choose the digit for Y in 4 ways.
 
So that's (5)(4) = 20 ways.

Each may be permuted in {{{5!/(2!3!)}}}{{{""=""}}}{{{10}}} distinguishable ways.

That's (20)(10) = 200

For both cases, that's 900+200 = 1100.

Edwin</pre>