Question 1208189
Hello here is the solution to your problem in steps.
Hope you find this helpful.
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Step 1: Understand the constraints
- Two queens cannot share the same row, column, or diagonal.
- A standard chessboard has 8 rows and 8 columns.

Step 2: Calculate the total possible placements for the first queen
- The first queen can be placed in any of the 64 squares (8 rows x 8 columns).

Step 3: Calculate the possible placements for the second queen
- After placing the first queen, the second queen cannot be placed in the same row, column, or diagonal.
- This means the second queen has 36 possible squares to be placed (64 - 28 squares that are under attack by the first queen).

Step 4: Account for overcounting
- Since the order of placing the queens doesn't matter, we need to divide the total count by 2 to avoid counting each configuration twice.

Step 5: Calculate the total possible ways
- Total possible ways = (Total possible placements for the first queen) x (Possible placements for the second queen) / 2
- Total possible ways = 64 x 36 / 2
- Total possible ways = 1152

The final answer is 1152.
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