Question 1208155
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How much water should be added to 12 mL of 8​% alcohol solution to reduce the concentration to 6​%?
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<pre>
Your original solution contains  0.08 * 12 = 0.96 mL  of pure alcohol.


You want to have the new total volume  V  such that  0.96 mL  of pure alcohol
make the concentration  0.06.


Write an equation saying that  0.06  of  V  is  0.96

    0.06*V = 0.96.


Solve it and find  V

    V = 0.96/0.06 = 16 mL.


So, the original volume is/was 12 mL; new volume should be 16 mL.

Hence,  16 - 12 = 4 mL of water should be added.


<U>ANSWER</U>.  4 mL of water should be added.


<U>CHECK</U>.    {{{0.96/16}}} = 0.06,  correct.
</pre>

Solved.