Question 1208098
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One solution is obvious:


            A = 0,    B = 0,    C = cr(2)-1.



3-1 = 2 other similar solutions can be found using permutations.



Several other solutions can be found easily.


Take A= 1,  B= -1,  C = cr(2)-1.


Check that it does satisfy equation.  


6-1 = 5 other similar solutions can be found using permutations.



Generally speaking,  there are infinitely many solutions in real numbers.   A  and  B  can be assigned by an arbitrary way,

and then value of  C  can be adjusted from the equation.



So,  without additional restrictions,  this  " problem "  makes a few sense.



In the form as presented,  this  " problem "  is good as a joke 
to make a reader laughing after several minutes of thinking.