Question 1208027
<pre>

{{{system(a[1]=2k+1,a[2]=5k-3,a[3]=7k-2,a[2]=a[1]+d, a[3]=a[2]+d)}}}

The last two equations give us the system

{{{system(5k-3=(2k+1)+d,7k-2=(5k-3)+d)}}}

Simplify those equations and solve the system by substitution
or elimination.  You will then have the values for k and d. Then
find a<sub>1</sub> by substituting the value for k in {{{a[1]=2k+1}}}.

Then write out the first 17 terms beginning with a<sub>1</sub> and 
add d over and over until you have 17 terms.

Oh, maybe by "17 term" you meant the "17th term" and not the "17 terms".

If so, use {{{a[n]=a[1]+(n-1)d}}} with n=17. 

Do the other one the same way.

Edwin</pre>