Question 1208022
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Assume that f(3) = 4. Name a point that must be on the graph of y= -5f(2x - 3) + 1
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<pre>
First, we want the argument 2x-3 be 3.


So, we write this equation

    2x - 3 = 3.


Then we solve it  and find  x = {{{(3+3)/2}}} = {{{6/2}}} = 3.



Next,  we want to calculate  y = -5f(2x-3) + 1.

We just know that 2x-3 is 3, because we found x in this way.
So, we write

    y = = -5f(3) + 1 = (at this point, we know and use that f(3)=4, so we continue) = -5*4 + 1 = -20 + 1 = -19.



Thus the point  (x,y) = (3,-19)  is on the graph  y = -5f(2x-3) + 1.


<U>ANSWER</U>.  If f(3) = 4,  then the point which must be on the graph  y = -5f(2x-3) + 1  is  (x,y) = (3,-19).
</pre>

Solved.



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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Coordinate-system/Given-a-point-on-a-plot-of-a-function--find-the-corresponding-point-on-the-plot-of-transformed-function.lesson>Given a point on a plot of a function, find the corresponding point on the plot of transformed function</A> 

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