Question 1208009

x^2+(23-x)^2 = 17^2   ( using Pythagoras theorem)

x^2 +529 -46x+x^2 = 289

2x^2 -46x -(529-289)=0

2x^2 -46x +240=0 is the required equation

comparing with ax^2+bx+c=0  we get

a=2, b=-46, c=240

*[illustration plot.png].
Corrected solution