Question 1207883
One of the most classic and routine of linear equation exercises.  Too easy to find this already published.


Your two points are as  (c, f)  and you could choose to keep this way and have {{{f=mc+b}}}; f for Fahrenheit and c for Celsius.


slope, m

{{{(212-32)/(100-0)}}}

{{{180/100}}}

{{{1.8}}}


If want point-slope form to start with then
{{{f-y=m(c-x)}}} for either of your points (x,y).

You could choose either.  What if you choose (0, 32).

{{{f-32=1.8(c-0)}}}

{{{f-32=1.8c}}}

{{{highlight(f=1.8c+32)}}}