Question 1207746
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Here is another non-algebraic way to solve the problem quickly and easily.<br>
The faster car finished the trip in 3 hours; the slower car finished in 3.5 hours.<br>
Since the distances are the same and the ratio of times is 3/3.5=6/7, the ratio of speeds is 7/6.<br>
Since the ratio of speed is 7/6 and the difference in speeds is 10mph, the two speeds are 70mph and 60mph.<br>
(You can reach that conclusion by observation and simple logical reasoning, or you can do it more formally using a proportion.)<br>
ANSWERS:
speed of faster car: 70mph
speed of slower car: 60mph
distance each car traveled: 70(3)=210 miles, or 60(3.5)=210 miles<br>