Question 1207843
<pre>
I wish you wouldn't use that notation.  I looked it up and
from what I read it means this.  Let me know if it means
something else:

\log_6 (\frac{216^x}{1296^x})\log_x6

means this, I think:

{{{log(6,(216^x/1296^x))*(log(x,(6)))}}}

Use the rule {{{a^n/b^n=(a/b)^n}}}

{{{log(6,(216/1296)^x)*(log(x,(6)))}}}

Reduce the fraction, and use the rule {{{log(a,(b))=1^""/log(b,(a))}}}

{{{log(6,(1/6)^x)*expr(1^""/(log(6,(x))))}}}

Move the exponent x out front:

{{{x*log(6,(1/6))*expr(1^""/(log(6,(x))))}}}

Write {{{1/6}}} as {{{6^(-1)}}}

{{{x*log(6,(6^(-1)))*expr(1^""/(log(6,(x))))}}}

Move the exponent -1 out front as a negative sign

{{{-x*log(6,(6))*expr(1^""/(log(6,(x))))}}}

Use the rule {{{log(a,(a))=1}}}

{{{-x*1*expr(1^""/(log(6,(x))))}}}

{{{-x^""/log(6,(x))}}}

Edwin</pre>