Question 1207745
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Here is a solution by an informal method that can be used to solve any 2-part "mixture" problem like this (if formal algebra is not required).<br>
To make a profit of $3 on each box if the selling price is $12.50, the cost of production needs to be $12.50-$3 = $9.50.<br>
The cost of producing 30 caramels would be 30($0.25) = $7.50; the cost of producing 30 cremes would be 30($0.45) = $13.50.
Use mental arithmetic to see that $9.50 is 1/3 of the way from $7.50 to $13.50.
That means 1/3 of the candies should be the more expensive cremes.<br>
1/3 of 30 is 10.<br>
ANSWER: 10 cremes and 20 caramels<br>