Question 1207695
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{{{a-b=4}}} [1]<br>
{{{a^2-b^2=8}}} [2]<br>
Factor [2] and substitute [1]:<br>
{{{a^2-b^2=(a+b)(a-b)=(a+b)(4)=8}}}
{{{a+b=8/4=2}}} [3]<br>
Add [1] and [3]:<br>
{{{2a=6}}}
{{{a=3}}} [4]<br>
Substitute [4] in [3]:<br>
{{{3+b=2}}}
{{{b=-1}}}<br>
Solution: a=3; b=-1<br>
ANSWERS:
(a) ab = (3)(-1) = -3
(b) a+b = (3)+(-1) = 2
(c) a=3; b=-1<br>