Question 1207695


{{{a - b = 4 }}}.......eq.1

 {{{a^2 - b^2 = 8}}}

 {{{(a - b)(a+b)= 8}}}....eq2, substitute {{{a-b}}}

{{{4(a+b)= 8}}}

{{{a+b= 2}}}........solve for {{{b}}}

{{{b=2-a}}}..........eq.2a


go to

{{{a - b = 4}}} .......eq.1, substitute {{{b}}}

{{{a - (2-a) = 4 }}}

{{{a - 2+a = 4 }}}

{{{2a=4+2}}}

{{{2a=6}}}

{{{a=3}}}


go to

{{{b=2-a}}}..........eq.2a, substitute {{{a}}}

{{{b=2-3}}}

{{{b=-1}}}

solution: {{{a=3}}}, {{{b=-1}}}


(a) Find all possible values of {{{ab}}}

{{{ab=3(-1)=-3}}}


(b) Find all possible values of {{{a+b}}}

{{{a+b=3+(-1)=2}}}


(c) Find all possible values of {{{a}}} and {{{b}}}

{{{a=3}}}, {{{b=-1}}}