Question 1207669
.
A civil engineer relates the thickness T, in inches, and height H, in feet, of a square wooden pillar to its crushing load L, in tons, using the model 

T = [(LH^2)/25)]^(1/4). 

If a square wooden pillar is 4 inches thick and 10 feet high {{{highlight(cross(l))}}} <U>H</U>, what us the crushing load?


Here is my set up:


4 = [(L(10)^2)/25)]^(1/4). 


Is this correct?


Thanks.
~~~~~~~~~~~~~~~



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;*************************

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;See my editing.

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;*************************



Your set up is correct.


So far, so good.


Next, you need to find the crushing load L from your equation.