Question 1207662
that looks reasonable, although it might get messy.


you can also do the following:


in the equation  k^2 - 3k = 28, subtract 28 from both sides to get:
k^2 - 3k - 28 = 0
factor this quadratic equation to get:
(k-7) * (k+4) = 0
solve for k to get:
k = 7 or k = -4


in the equation k = (x + 3)/(x - 4), replace k with 7 and solve for x.  
after you do that, replace k with - 4 and solve for x.


you should get x = 31/6 or x = 13/5.


it should be able to be solved the way that you showed, but i think solving for k first is probably easier.