<PRE><B>Question 1207651</B>
&lt;br&gt;
Let I, J, and K represent the amounts Iris, Jolene, and Karen contributed, respectively.&lt;br&gt;
Let x be the total cost.&lt;br&gt;
Then....&lt;br&gt;
I+J = (3/5)x
I+K = (13/20)x&lt;br&gt;
Add the two equations:&lt;br&gt;
2I+J+K= (3/5)x + (13/20)x = (12/20)x + (13/20)x = (25/20)x = (5/4)x&lt;br&gt;
But&lt;br&gt;
I+J+K = x&lt;br&gt;
so&lt;br&gt;
I = (2I+J+K)-(I+J+K) = (5/4)x-x = (1/4)x&lt;br&gt;
So Iris paid 1/4 of the total, which means Jolene and Karen together paid 3/4 of the total.  Jolene and Karen together spent $195:&lt;br&gt;
(3/4)x = 195
x = 195*(4/3) = 260&lt;br&gt;
The total cost was $260.&lt;br&gt;
So the amount Iris paid was 1/4 of $260, or $65.&lt;br&gt;
Iris and Karen together paid 13/20 of the total; Iris and Jolene together paid 3/5 of the total.  The difference between those amounts is the difference between what Karen paid and what Jolene paid:&lt;br&gt;
I+K = (13/20)x
I+J = (12/20)x
K-J = (I+K) - (I+J) = (1/20)x&lt;br&gt;
Karen spent (1/20)x = $13 more than Jolene; and together the two of them spent $195.  Use formal algebra or informal logical reasoning and simple arithmetic to determine that Karen spent $104 and Jolene spent $91.&lt;br&gt;
Now we have the amounts that each of them spent:&lt;br&gt;
Iris: $65
Jolene: $91
Karen: $104&lt;br&gt;
ANSWER: Jolene spent $91-$65 = $26 more than Iris.&lt;br&gt;
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