Question 1207641
this is what i get.


let x = number of men
let y = number of women


you are given that 20% of men and 25% of women are unmarried.


the equation for that is .2x + .25y = number of unmarried employees.


a total of 230 employees are unmarried.


the equation for that is .2x + .25y = 230


the number of unmarried men and unmarried women are equal.


that gets you .2x = .25y


if .2x + .25y = 230, and .2x = .25y, then replace .2x with .25y to get:
.25y + .25y = 230
combine like terms to get .5y = 230
solve for y to get y = 230 / .5 = 460.


likewise replace .25y with .2x to get:
.2x + .2x = 230
combine like terms to get:
.4x = 230
solve for x to get x = 230 / .4 = 575.


you have 575 men and 460 women for a total of 1035 employees.


the percentage of women is 460 / 1035 * 100 = 44.4444444.....%.


the percent is a fraction, but the number of employees is not.


working from the beginning, you have:


575 men and 460 women.
20% of the men and 25% of the women are unmarried.
that makes .20 * 575 + .25 * 460 unmarried employees = 115 men and 115 women that are unmarried.
that makes a total of 230 employees that are unmarried, with the number of unmarried men being equal to the number of unmarried women.


let me know if this helps.
theo