Question 1207616
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You have a total supply of 1000 pieces of candy, and an empty vat.  You also have a machine 
that can add exactly 10 pieces of candy per scoop to the vat, and another machine that can remove 
exactly 3 pieces of candy with a different scoop from the vat.  When these two machines are done, 
there is only one piece of candy left in the vat.  What is the smallest possible number of times 
the the first machine added candy to the vat?
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The answer is absolutely clear and obvious for everybody, who will read the problem
to  the end.


        The smallest possible number of times 
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;the first machine added candy to the vat is 1 (one).    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>



<U>Explanation</U>.  &nbsp;One is good and does work, &nbsp;since if &nbsp;10 &nbsp;pieces of candies were added sometime 
using one scoop once, &nbsp;then &nbsp;1 &nbsp;candy was left when the other scoop took off &nbsp;3 &nbsp;candies three times.



Evaluating the problem from the point of view of its contents, 
I would say that it has very poor contents, where the word &nbsp;"poor"
is used as an antonym to the word &nbsp;"rich".



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Lord, &nbsp;save from such problems in the future.