Question 1207569
<br>
{{{(-8i)^(1/3)}}}<br>
Write the given complex number in cis(theta) form:<br>
{{{(8cis(270))^(1/3)}}}<br>
Use deMoivre's Theorem to find the principal root:<br>
{{{((8^(1/3))(cis(270/3)))=2cis(90)}}}<br>
Convert the result back to a+bi form:<br>
{{{2(0+i)=2i}}}<br>
ANSWER: 2i<br>
CHECK:
{{{(2i)^3=8i^3=8(-i)=-8i}}}<br>