Question 1207535
<pre>
Let the volume of a small box be S cubic units.
Let the volume of a big box be B cubic units.
Then the volume of the container is 60S = 48B cubic units.
Let x be the number of big boxes more the container can still hold.
The container already contains 20S+24B cubic units.
The container can hold x*B more cubic units.
{{{matrix(1,7,
matrix(1,3,Volume, of, container),""="",60S,""="",48B,""="",20S+24B+x*B))}}}

{{{60S=48B}}}
{{{S=expr(48/60)B}}}
{{{S=0.8*B}}}

{{{48B=20S+24B+x*B}}}
{{{48*B=20(0.8B)+24*B+x*B}}}
{{{48*B=16B+24*B+x*B}}}
Divide through by B
{{{48=16+24+x}}}
{{{48=40+x}}}
{{{8=x}}}

So it'll hold 8 more big boxes.

Edwin</pre>