<PRE><B>Question 1207535</B>
A container can hold either 60 small boxes or 48 big boxes.
 If there are already 20 small and 24 big boxes in the container how many more big boxes can the container still hold. 
:
let a full box = 1
Each small box = 1/60
Each big box  = 1/48
let b = no. of big boxes is can still hold
:
{{{20/60}}} + {{{24/48}}} + {{{B/48}}} = 1
convert to a common denominator of 48
{{{16/48}}} + {{{24/48}}} + {{{b/48}}} = {{{48/48}}}
same as 
16 + 24 + b = 48
b = 48-40
b = 8 more big boxes
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