Question 1207477
One of the factors is {{{(x-(2+3i))}}} and the other factor is {{{(x-(2-3i))}}}.


Equation may start as {{{(x-(2+3i))(x-(2-3i))=0}}}.


A little bit of algebra,  {{{(x-2-3i)(x-2+3i)=0}}}.
{{{((x-2)-3i)((x-2)+3i)=0}}}
{{{(x-2)^2-(3i)^2=0}}}
Now, you take this the rest of the way.


Much of the steps for this example are not necessary, since complex solutions for quadratic equations come in conjugate pairs.