Question 1207452
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As the other tutor mentions, the only solution is x = 1.


The other value x = -2 is extraneous. 


Here's the graph mentioned.
{{{ graph( 500, 500, -10, 10, -10, 10, 2x, sqrt(8-4x)) }}}


Let's reflect the square root curve over the x axis to handle {{{y = -sqrt(8-4x)}}}
{{{ graph( 500, 500, -10, 10, -10, 10, 2x, sqrt(8-4x),-sqrt(8-4x)) }}}
Notice the new intersection point (-2,-4) which is the intersection of y = 2x and y = -sqrt(8-4x)


So if we were allowed to plot the plus minus of {{{sqrt(8-4x)}}} then we'd get two solutions for x.
However, we only plot the positive version.
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