Question 1207452


{{{ 2x=sqrt(8-4x) }}}....square both sides

{{{ 4x^2=8-4x }}}....divide by {{{4}}}

{{{ x^2=2-x }}}

{{{ x^2+x-2=0 }}}...factor

{{{ x^2+2x-x-2=0 }}}

{{{ (x^2+2x)-(x+2)=0 }}}

{{{ x(x+2)-(x+2)=0 }}}

{{{ (x-1)(x+2)=0 }}}


solutions:

{{{x=1}}}

{{{x=-2}}}


verify solutions:

{{{ 2*1=sqrt(8-4*1) }}}=>{{{ 2=2 }}}=> true

{{{ 2*(-2)=sqrt(8-4*(-2)) }}}=>{{{ -4=4}}}=> false


so, your solution is {{{x=1}}}


{{{ graph( 600, 600, -10, 10, -10, 10, 2x, sqrt(8-4x)) }}}