Question 1207406
.
<pre>

(1)  Yes.



(2)  Example of repeated solutions

        {{{(x-1)^2}}} = 0,

     which is the same as

        {{{x^2 - 2x + 1}}} = 0.



(3)  Example of "no solutions"

        {{{(x-1)^2}}} + 1 = 0,

     which is the same as

        {{{x^2 - 2x + 2}}} = 0.
</pre>

Solved, answered and explained.