<PRE><B>Question 1207400</B>
&lt;br&gt;
A formal algebraic solution....&lt;br&gt;
Let x be the age of Kenneth&#39;s father
Then x-36 is Kenneth&#39;s age&lt;br&gt;
x+7 = father&#39;s age in 7 years
(x-36)+7 = x-29 = Kenneth&#39;s age in 7 years&lt;br&gt;
In 7 years, the father&#39;s age will be twice Kenneth&#39;s age:&lt;br&gt;
x+7=2(x-29)
x+7=2x-58
65=x&lt;br&gt;
ANSWER: 65&lt;br&gt;
CHECK: x+7=65+7=72; x-29=65-29=36; 72=2*36&lt;br&gt;
Informally (using logical reasoning and simple mental arithmetic, which is good exercise)....&lt;br&gt;
The difference in their ages is 36; when the father is twice as old, their ages will be 72 and 36.  That will be 7 years from now, so the father&#39;s age now is 72-7 = 65&lt;br&gt;

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