Question 1207376
<pre>


{{{drawing(400,325,-3,13,-3,10,

line(-2,-2,10,-2), line(10,-2,10,0), line(10,0,-2,0), line(-2,0,-2,-2),
line(-2,0,0,0), line(0,0,0,9), line(0,9,-2,9), line(-2,9,-2,0),
line(0,7,12,7), line(12,7,12,9), line(12,9,0,9), line(0,9,0,7),
line(10,-2,12,-2), line(12,-2,12,7), line(12,7,10,7), line(10,7,10,-2),

locate(5,.7,30), locate(9.3,3.6,21), locate(10.8,.7-2,x)

)}}}

The frame is four rectangles, two are (30+x) by x and two are (21+x) by x.

So

{{{2(30+x)x + 2(21+x)x = 188}}}

That simplifies to: 

{{{4x^2+102x-188=0}}}

Divide through by 2:

{{{2x^2+51x-94=0}}}

Solve by the quadratic formula:

 {{{x = (-51 +- sqrt(51^2-4*2*(-94) ))/(2*2) }}}

{{{x = (-51 +- sqrt(2601+752 ))/4 }}} 

{{{x = (-51 +- sqrt(3353))/2 }}} 

Ignore the minus

{{{x = (-51 + sqrt(3353))/2 }}}

About x = 1.726273692 cm = width of frame.  Round off as you were told. 

Edwin</pre>