Question 1207360
Rationalize the denominator.

Let cr = cube root.

5/(cr(2))
<pre>
{{{5^""/root(3,2)}}}{{{""=""}}}{{{expr(5^""/root(3,2))*expr(root(3,2)/root(3,2))*expr(root(3,2)/root(3,2))}}}{{{""=""}}}{{{5root(3,4)/root(3,2^3)}}}{{{""=""}}}{{{5root(3,4)/2^""}}}

Let's use "cr" instead of the standard {{{root(3,"")}}}

{{{5^""/cr(2^"")}}}{{{""=""}}}{{{expr(5^""/cr(2^""))expr(cr(2^"")/cr(2^""))expr(cr(2^"")/cr(2^"")))}}}{{{""=""}}}{{{5*cr(2^2)/cr(2^3)}}}{{{""=""}}}{{{5*cr(4^"")/2^""}}}

Edwin</pre>