Question 1207356
If 9-digit number 2018A902B is divisible by 144, find the value of A+B

16*9 =144
the number should be divisible by 16 and 9

Divisibility test for 16
The number has 9 digits

the last 4 digits of the number should be divisible by 16 

902B  is divisible by 16 if B = 4 

if number is divisible by 9 then sum of digits must be 9
plug 4 in B

2018A9024
sum should be 9

The above number sum of digits is 26+A    ( 9*3=27)
So A =1

A=1 B=4

A+B = 5
The number is 

201819024  

201819024  /144 =1401521

It works