<PRE><B>Question 116003</B>
Multiply the fraction.
(2x squared - x - 3 OVER 3x squared + 7x + 4)(3x squared - 11x - 20 OVER
4x squared - 9)
:
Write it:
{{{((2x^2-x-3))/((3x^2+7x+4))}}} * {{{((3x^2-11x-20))/((4x^2-9))}}}
:
Look carefully all these quadratics can be factored
{{{((2x-3)(x+1))/((3x+4)(x+1))}}} * {{{((3x+4)(x-5))/((2x-3)(2x+3))}}}
:
You can see that the following can be canceled: (2x-3); (x+1); (3x+4) leaving:
{{{((x-5))/((2x+3))}}}
:
After canceling, you just end up multiplying by 1</PRE>