Question 1207299




let original amount John had be {{{x}}}

John spent {{{1/2}}} of his money in the supermarket: so, we have {{{x/2}}}

and 

{{{1/3}}} in the store: so, we have {{{x/3}}}


he spent total of {{{x/2+x/3}}} and still has ${{{100}}}

sum of all he spent and he still have must be equal to original amount


{{{x=x/2+x/3+100}}}....solve for {{{x}}}

{{{x-x/2-x/3=100}}}

{{{(6x-3x-2x)/6=100}}}

{{{x/6=100}}}

{{{x=600}}}

John  originally did have ${{{600}}}