Question 1207296
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You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. 
You replace the first tile in the bag and then choose again. Find ​P(Upper A and Upper A ).
Question content area bottom
Part 1
​P(Upper A and Upper A) equals =
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<pre>
Total tiles in the bag is 3+2+4 = 9.


P(A) = {{{number_of_As_tiles/total_tiles}}} = {{{3/9}}} = {{{1/3}}}.


Since choosing is with replacement, the conditions to choose the second tile are the same 
as for the first tile.


THEREFORE,  P(A and A) = P(A)*P(A) = {{{(1/3)*(1/3)}}} = {{{1/9}}}.    <U>ANSWER</U>
</pre>

Solved.